FIBS Board backgammon forum

There's this dice problem that I'm faced with and I need help from you guys. We have 4 dice that are rolled once and the results are: two 6's and two 5's on top. I am asked to add the dice and the answer isn't as simple as 6+6+5+5 = 22. A hint tells me that the answer is between 100 and 200.

How can I possibly solve that problem? maybe it has to do with probabilities?

(Dice are six-sided)


EDIT: The answer is 177. How can I arrive at such an answer?

Thanks

find an answer between 100 and 200.
65+65=130  :blink:

Ah, Tomawaky's arrangement of the digits suggests this: 56 + 55 + 66 = 177, but why that would be the answer escapes me.

If the dice are viewed obliquely, they could be arranged so that:
Die 1 has 6 on top with 4 & 5 showing
Die 2 has 6 on top with 3 & 2 showing
Die 3 has 5 on top with 6 & 4 showing
Die 4 has 5 on top with 3 & 6 showing

645 + 632 - 564 - 536 = 177

If there was prize money involved, you owe me at least half!

:yes:

 :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus: :applaus:

Quote from: stiefnu on January 08, 2009, 04:32:10 PM
645 + 632 - 564 - 536 = 177

Hey, who said anything about subtraction? ;)

Hmm, you may have a point there.  But, then again, you could think of it as negative addition...   :wacko: